An easy riddler!!!!!!!!!?!
Question: An easy riddler!!!!!!!!!!?
Daniel, my son, is exactly one fifth of my age!. In 21 years time, I will be exactly twice his age!. My wife is exactly seven times older than my daughter, Jessica!. In 8 years time, my wife will be three times older then Jessica!. How old are Daniel and Jessica now!?
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Answers:
let father's age = x
then daniel's age = x/5
21 + x = 2(x/5 + 21)
21 +x = 2x/5 + 42
105 + 5x = 2x + 210
35 = x = father's age
now daniel's age = x/5 = 35/5 = 7
let jessica's age = y
then mother's age = 7y
7y + 8 = 3(y + 8)
7y + 8 = 3y +24
4y = 16
y = 16/4
y = 4 = jessica's age
daniel's age = 7 yrs
jessica's age = 4 yrs
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then daniel's age = x/5
21 + x = 2(x/5 + 21)
21 +x = 2x/5 + 42
105 + 5x = 2x + 210
35 = x = father's age
now daniel's age = x/5 = 35/5 = 7
let jessica's age = y
then mother's age = 7y
7y + 8 = 3(y + 8)
7y + 8 = 3y +24
4y = 16
y = 16/4
y = 4 = jessica's age
daniel's age = 7 yrs
jessica's age = 4 yrs
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Daniel is 7 years old and Jessica is 4 years old!.
And aswell as that you are 35 and your wife is 28!. xDWww@Enter-QA@Com
And aswell as that you are 35 and your wife is 28!. xDWww@Enter-QA@Com
Daniel = 7
Jess = 4Www@Enter-QA@Com
Jess = 4Www@Enter-QA@Com
daniel 7yrs
jessica 4yrsWww@Enter-QA@Com
jessica 4yrsWww@Enter-QA@Com
5 + 3Www@Enter-QA@Com