Can you solve this tricky riddle?!


Question: Can you solve this tricky riddle!?
A teacher hands out candies to her class, 3 days in a row!.

There are 20 kids in the class

day 1:There are 20 kids here, 7 candies left!.

day 2!. There are 18 kids here, 7 candies left!.

day 3!. There are 17 students, 0 left!.

How many candies were there in total that the teacher EQUALLY distributed to everyone!. How much was each student given!.

*This is hard, I don't think anyone will be able to solve it!.Www@Enter-QA@Com


Answers:
There is a total of 187 pieces of candy each day!.

On Day 1: there are 20 children and each get 9 pieces of candy!. That means that 9*20=180 get passed out leaving 7 candies left over!.

On Day 2: there are 18 children and each get 10 pieces of candy!. That means that 10*18=180 get passed out leaving 7 candies left over!.

On Day 3: there are 17 children and each get 11 pieces of candy!. That means that 11*17=187 get passed out leaving 0 candies left over!.

The total amount of candy that the teacher purchased for all three days was 3*187= 561, but the teacher only brought in 187 pieces each day!.

booyah!Www@Enter-QA@Com

I don't think this is a riddle, this is a mathematical question!. But if you wanna get the answer try solving the question algebraically first by trying to find the number of candies then it's easy to solve this question!. Don't really know the answer but I saw my dad doing this kind of stuff!. But I think he gave each student 3 candies!.
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ther was 55 candies to begin with!. she equally distributed 51 to 17 students who each got 3Www@Enter-QA@Com

The candies were m&ms and she gave 1 m&m to everyone and ate the rest!.!.!. There were 8 packs!.Www@Enter-QA@Com

0_oWww@Enter-QA@Com

420Www@Enter-QA@Com

41Www@Enter-QA@Com

i dont think she gave any out i think she ate it on tha last dayWww@Enter-QA@Com

ow my head hurts
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