Numerical riddle...Someone who's really good with numbers?!
Question: Numerical riddle!.!.!.Someone who's really good with numbers!?
I need 6 numbers and the last number has to be the number 8
Odd and even numbers alternate ( Zero is an even number )
The difference of adjacent digits is always bigger than one
The first two digits (if read as one number for example 14) as well as the two middle digits (if read as one number) are multiples of the last two digits!. (if read as one number!.)
Those are the clues I have and I don't know the answer!. I'm looking for someone to help me out!. I'm playing a game on my cell phone called Escape and to exit one room and get into another room you have to figure out the access code to the door!. Www@Enter-QA@Com
Odd and even numbers alternate ( Zero is an even number )
The difference of adjacent digits is always bigger than one
The first two digits (if read as one number for example 14) as well as the two middle digits (if read as one number) are multiples of the last two digits!. (if read as one number!.)
Those are the clues I have and I don't know the answer!. I'm looking for someone to help me out!. I'm playing a game on my cell phone called Escape and to exit one room and get into another room you have to figure out the access code to the door!. Www@Enter-QA@Com
Answers:
It seems there are multiple possibilities if duplicates are allowed!. If not the answer is:
90 36 18
The final two numbers could be 18, 38, or 58!. (78 and 98 don't qualify because the difference of adjacent numbers must be > 1)!. 08, 28, etc!.!.!. don't because of alternating evens and odds!.
If 18, the posibilities for the other pairs are 18, 36, 72, 90 (54 is no good)!. The middle pair cannot be 72 or 90 because 0/2 would be next to the 1 in "18" leaving 36 as the middle!. 72 is out as the first pair (2 in "72" next to the 3 in "36")!. That leaves
90 36 18
If duplicates are allowed these are the other possibilities:
18 18 18
36 36 18
18 36 18
36 18 18
72 18 18
90 18 18
58 58 58 (no other multiple < 100)
38 38 38 (76 is no good)Www@Enter-QA@Com
90 36 18
The final two numbers could be 18, 38, or 58!. (78 and 98 don't qualify because the difference of adjacent numbers must be > 1)!. 08, 28, etc!.!.!. don't because of alternating evens and odds!.
If 18, the posibilities for the other pairs are 18, 36, 72, 90 (54 is no good)!. The middle pair cannot be 72 or 90 because 0/2 would be next to the 1 in "18" leaving 36 as the middle!. 72 is out as the first pair (2 in "72" next to the 3 in "36")!. That leaves
90 36 18
If duplicates are allowed these are the other possibilities:
18 18 18
36 36 18
18 36 18
36 18 18
72 18 18
90 18 18
58 58 58 (no other multiple < 100)
38 38 38 (76 is no good)Www@Enter-QA@Com
im building a time machine and going back in time to kill the guy who invented Math
so in a few days this question wont make any sense
so in a few weeks you wWww@Enter-QA@Com
so in a few days this question wont make any sense
so in a few weeks you wWww@Enter-QA@Com
are the numbers all one digit!?
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