I need help so here's the question. Choose any number with any digits. Then !
Question: I need help so here's the question!. Choose any number with any digits!. Then subtract 2, multiply the result by!?
3 add 12 divide the answer by 3 add 5 now subtract the number u began with!. I bet u you'll end up with 7! I'll give you 5 points if you figure it out! Thanks!
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Answers:
it's always 7 because there's a pattern or something
i learned that a long time ago but i don't know how to explain it
it has something to do with the number you chose canceling itself
i wrote an expression for it and solved (x represents the number that you choose):
[3(x-2)+12]/3+5-x
=(3x-6+12)/3+5-x
=(3x+6)/3+5-x
=x+2+5-x **x cancels itself out here because x-x=0**
=2+5
=7Www@Enter-QA@Com
i learned that a long time ago but i don't know how to explain it
it has something to do with the number you chose canceling itself
i wrote an expression for it and solved (x represents the number that you choose):
[3(x-2)+12]/3+5-x
=(3x-6+12)/3+5-x
=(3x+6)/3+5-x
=x+2+5-x **x cancels itself out here because x-x=0**
=2+5
=7Www@Enter-QA@Com
Okay, I choose 13!.
13-2 = 11
11x3 = 33
33+12 = 45
45/3 = 15
15+5= 20
20-13 = 7!
Cool!Www@Enter-QA@Com
13-2 = 11
11x3 = 33
33+12 = 45
45/3 = 15
15+5= 20
20-13 = 7!
Cool!Www@Enter-QA@Com
3-2= 1
3+12 =15
15/3 =5
5+5 =10
10-3 = 7
Woo hooWww@Enter-QA@Com
3+12 =15
15/3 =5
5+5 =10
10-3 = 7
Woo hooWww@Enter-QA@Com
5-2=3
3x3=9
9+12=21
21/3=7
7+5=12
12-5=7
cool Www@Enter-QA@Com
3x3=9
9+12=21
21/3=7
7+5=12
12-5=7
cool Www@Enter-QA@Com
wow lol this really did work Www@Enter-QA@Com
the answer is 7!. we had that riddle in my basic math classWww@Enter-QA@Com