Thought provoking challenge, if you're up for it?!


Question: Thought provoking challenge, if you're up for it!?
Ok I got this logic problem I can't seem to figure out

There are 9 coins!. 1 of the coins has a different mass from the others!. You don't know if it has more or less weight!. You have a scale that you can use only 3 times!. How can you find the odd coin!?Www@Enter-QA@Com


Answers:
Coins are 123 456 789

Put Coins 123 on one side and 456 on the other!.!.
If they weight the same then 789 has the coind that doesn't match!.
In which case weigh 7 and 9 if they weigh the same then 8 is the one that doesn't match other wise put 7 and 8 on the scale if they weight the same then 9 doesn't match otherwise 7 doesn't match!.

If 123 and 456 weigh different!. Put 14 and 25 on the scale!. If they weigh the same then put 3 and 7 on the scale if they weigh the same then it's 6 if they don't then it's 3

Now if 14 and 25 weigh different then you need to know if 123 or 456 weighed more!.

If 123 weighed more than 456 and 14 weighs more than 26 then 1 or 5 is the odd coin!. Put 1 on with 9 if they weigh the same then it's 5 if they don't then it's 1!. If 123 weighed more than 456 and 14 weighs less than 25 then 2 or 4 is the odd coin weigh 2 against 9 if they are the same the odd coin is 4 if they aren't then it's 2!.

If 123 weighed less than 456 and 14 weighs less than 25 then 1 or 5 is the odd coin!. Put 1 on with 9 if they weigh the same then it's 5 if they don't then it's 1!. If 123 weighed less than 456 and 14 weighs more than 25 then 2 or 4 is the odd coin weigh 2 against 9 if they are the same the odd coin is 4 if they aren't then it's 2!.

Www@Enter-QA@Com

put 4 on 1 side and four on the other:

if equal: remaing coin weighs more

if unequal: take the heavier side and put two on each side

then take the heavier side and put one on each side, heavier one is heavier!Www@Enter-QA@Com

heres the website that gives u the answer but u only need to use the scale twice:

http://www!.dontmakemelaugh!.com/joke!.asp!?!.!.!.

(best answer please) =]

oh ok then i tried working it out!. (but i couldn't finish maybe u can figure it out after this) and this is what i got:

ok so u can divide the coins in three equal groups!. and ill name them 3A, 3B, 3C for each group so we wont be confused!. then take group 3A and 3B and put it on the scale!. and see which one is heavier and which one is lighter!. we'll pretend that 3A is heavier!. and then take 3A out and put 3C instead!. now if 3C is also heavier than 3B then 3B has the odd coin!. but if 3C is equal to 3B then 3A is the odd one out!. the only way for 3C to have the odd coin is if in the beginning, 3A and 3B are equal!. but we're pretending that 3A is heavier than 3B!. and now we're gonna pretend that 3C is heavier than 3B so 3B has the odd coin!. now we used the scale two times!. and then now get two of the 3 coins in 3B and put it on the scale, if theyre equal then the one u didnt put on is the odd coin!. (and now i dont know what happens if theyre not equal) Sorry!


ok i read Blacky B's comment and i thought that it was right at first but then, how do we know if the odd coin is heavier than the other's!? it might be lighter!. not trying to be offensive to u though Blacky B but just trying to help out!. maybe im wrong!.!.!.!.!.!.!.!.Www@Enter-QA@Com



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