Super hard problem -- Can you solve it!?!
Question: Super hard problem -- Can you solve it!!?
Three pimps buy 15 lbs of crack!. One pimp kills another and takes his 1/3!. The other pimp smokes 0!.004 lbs of the crack before he kills the other pimp!. A cop sees the murder and arrests the pimp while confiscating the crack and taking 2 lbs!. The left over crack is left in the pimps house where his bit*h finds it and smokes 0!.012 lbs before selling the rest to Tino who dilutes it to a mixture of 67% crack/ 33% baking soda!. He then sells the diluted crack (in 7 equal portions) to buyers!. Mike bought one of the portions; how much does his sample weigh!?Www@Enter-QA@Com
Answers:
The sample weighs 2!.769 lbs just prior to Mike ODing!. It's simple but everyone else is messing it up!. There was 15 lbs to start, taken down to the 12!.xx number that diane figured!. The dilution does not take away from the crack that is there, it just adds weight!. Everyone else is going the wrong direction with it, so the sample should weigh more than this 12!.xx/7, meaning that 2!.769 lbs is the sample size!. If you personally make the sample size less, you'll understand this better!.Www@Enter-QA@Com
After 1 pimp kills the first 1, 1 pimp has 10 lbs, the other has 5 lbs!.
The 2nd pimp smokes 0!.004 lbs, so he has 4!.996 lbs!.
*I assume he takes the 1st pimp's crack*
so in total, the remaining pimp has 14!.996 lbs!.
The cop arrests him, takes 2 lbs, so leaving 12!.996 lbs at his house!.
0!.012 lbs is smoked, leaving 12!.984 lbs!.
Diluting it makes no difference to the actual weight of crack Mike buys, so he gets:
12!.984/7 lbs = 1!.855 lbsWww@Enter-QA@Com
The 2nd pimp smokes 0!.004 lbs, so he has 4!.996 lbs!.
*I assume he takes the 1st pimp's crack*
so in total, the remaining pimp has 14!.996 lbs!.
The cop arrests him, takes 2 lbs, so leaving 12!.996 lbs at his house!.
0!.012 lbs is smoked, leaving 12!.984 lbs!.
Diluting it makes no difference to the actual weight of crack Mike buys, so he gets:
12!.984/7 lbs = 1!.855 lbsWww@Enter-QA@Com
Are you trying to find out how much your crack really weighs!? Excluding the baking soda, or with!?
Edit:
With the baking soda eh!?
Well, it wouldn't really matter then!. Cuz either way, "Mike" has been ripped off to the core!. :PWww@Enter-QA@Com
Edit:
With the baking soda eh!?
Well, it wouldn't really matter then!. Cuz either way, "Mike" has been ripped off to the core!. :PWww@Enter-QA@Com
wow!.!. you have to be a mathematician to solve that!.!. That is indeed a really hard problem!.!. !.hope you'll get the answer if it's really important to you!.!.Www@Enter-QA@Com
Who cares about Mike!? I just beat the **** out of him and stole the crack!. Gonna head down to the grade school and sell it to 3rd graders!.Www@Enter-QA@Com
What the hell!? Are you a dealer or something!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!.!.!.Www@Enter-QA@Com
WOW u know alot about crack!. Well i dont know nuthin about it so im just gonna say!.!.!.enough!.Www@Enter-QA@Com
::what the hell!.!.are you a math wizard or what!?!?!.!.!.>_<::Www@Enter-QA@Com
ok it's like 5 in the a!.m, but i'll take a stab at this!.!.!.i may be getting to literal but here i go *sigh* we start out with 15 lbs that ends up at one house current!? minus the !.004 =14!.996, then minus 2 the cop takes=12!.996 minus the !.012 smoked=12!.984!. now 12!.984 is how much crack we have to work with!. so that number isnt going to change that's what we have!. now since we have 7 portions, the crack at 100% would weight 1!.8548571!. pure crack!. but the mixture is 67% to 33% which shouldnt change the final 1/7 sell weight, but it will just change the make up!. so instead of 1!.8548571 lbs of pure crack for each portion it will be 1!.2427542 lbs of crack and !.6121029 of baking soda!. but it will in the end weigh 1!.8548571!. just not pure (67 +33=100 so still same about just different x and y factor to add up to answer)Www@Enter-QA@Com