?Question?????!
Question: !?Question!?!?!?!?!?
The distance from Philadelphia to Sea Isle City is 100 mi!. A car was driven this
distance using tires with a radius of 14 in!. How many revolutions of each tire
occurred on the trip!?Www@Enter-QA@Com
distance using tires with a radius of 14 in!. How many revolutions of each tire
occurred on the trip!?Www@Enter-QA@Com
Answers:
distance covered in 1rev of the tire = circumference of the tire
= 2TT r
= 2 x 22/7 x 14
=88in
Total no!.of rev= Total distance covered/
Total dist cover in 1 rev
= 100 mi/88 in
=100 x 63360 in/88in
( 1 mile= 63360 in)
= 72000 rev!.:))))Www@Enter-QA@Com
= 2TT r
= 2 x 22/7 x 14
=88in
Total no!.of rev= Total distance covered/
Total dist cover in 1 rev
= 100 mi/88 in
=100 x 63360 in/88in
( 1 mile= 63360 in)
= 72000 rev!.:))))Www@Enter-QA@Com
Well, the circumference of the tires would be 2(pi)r!. (6!.28 x 14) in!. 87!.92 in!.
So the car would travel 87!.92 in!. for every tire revolution!. 1 mile is 5280 feet!. 5280 x 12 = 63,360 in!. 100 miles would then be 6,336,000 in!. Divide that by 87!.92 = about 72,065!.5 revolutions!.Www@Enter-QA@Com
So the car would travel 87!.92 in!. for every tire revolution!. 1 mile is 5280 feet!. 5280 x 12 = 63,360 in!. 100 miles would then be 6,336,000 in!. Divide that by 87!.92 = about 72,065!.5 revolutions!.Www@Enter-QA@Com
Sorry dude I am not a mathematician!.
!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.Cheers!.!.!.!.!.!.!.!.!.!.!.!.!.!.Www@Enter-QA@Com
!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.Cheers!.!.!.!.!.!.!.!.!.!.!.!.!.!.Www@Enter-QA@Com
haha what the heck this is retartedWww@Enter-QA@Com
sureWww@Enter-QA@Com
i dunnoWww@Enter-QA@Com