Does anyone want to help me with math problems??!


Question: Does anyone want to help me with math problems!?!?
suppose you have a bag that contains six blue marbles, two green marbles, three red marbles, and one white marble!. Find each probability!.

8!.) P(white)
10!.) P(red)
11!.) P( blue, then white when blue is not replaced)

Each letters D E T E R M I N E D
is written on a card!. you mix the cards thoroughly!. what is the probability of selecting an E, then an M!? the first card is replaced before selecting the second card!.

I cant do these, any one show me how to do them!? thanks so muchWww@Enter-QA@Com


Answers:
Here is my work
6Blue
2Green
3Red
1White
12 TOTAL
8!. 1/12
9!.1/4
10!. 1/22

DETERMINED 3/90
I think these are rightWww@Enter-QA@Com

wow easy!.!.!.
ok the bag one means you have 12 marbles!.
you have a 50% chance to get a blue marble!. you have a 25% chance to get a red marble!. you have a 1/12 chance (lazy to convert into percentage) to get a white marble and a 20% chance to get a green marble!.

ok i cant really figure out the determined one lol >!.< i dont get what you mean when you say the first card is replaced!. do you put it back in the bag!? do you switch it with another card then choose!. yeh i just dont get what you mean!. well i hope i helped you on the marble questionWww@Enter-QA@Com

First, find the total marbles you have(add all)!. So the probability of each color is how many of each over the total!.

If you can reduce it, do it!. Example 5/10 = 1/2

Next I'm not too sure about this but first find the probability of "E" and "M" the same way as the above!.

then MAY BE
(M * E) / Total
is the answer!.Www@Enter-QA@Com

on the first one add up how many there is in all then how many blue or red or ect!. and say theres 16 marbels 7 blue 3 red and 6 green blues probillity is 7/16Www@Enter-QA@Com

you should post this in the HOMEWORK HELP or MATHEMATICS sections!. this is not a joke or a riddle!. it's your homework!.Www@Enter-QA@Com

WHOA!! I think my brain just shut down!.Www@Enter-QA@Com



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