Can you solve this...?!


Question: When I take the digits 1, 2, 3, 4, and 5, how many different 5 digit numbers can be formed if you may not use the same digit twice in the number?


Answers: When I take the digits 1, 2, 3, 4, and 5, how many different 5 digit numbers can be formed if you may not use the same digit twice in the number?

120

5 x 4 x 3 x 2 x 1

eg if we take 1 2 3
3 x 2 x 1 = 6

123
132
213
231
312
321

Omg thats long i cba

=)

120

No. No, I can't solve it. :0(

1? 12345

1*2*3*4*5 = 120

12345, 12354, 12435, 12453, 12534, 12543, 13245
13254, 13425, 13452, 13524, 13542, 14235, 14253
14325, 14352, 14523, 14532, 15234, 15234, 15324
15342, 15423, 15432

Now just change the first digit and start again.

120 is the Answer.
Have a Nice Saturday!

you can create120 different combinations without repeating numbers in each group using the formula as quoted by Brain



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