Puzzle Help 2?!


Question: (Professor Layton for the DS Lite)
Nine squares are carved into a piece of wood.
Arrange nine unique numbers between i and 51 so that any three numbers have the same sum when added vertically, horizontally, or diagonally.
While several combinations are possible, your task is to find the number that occupies the middle square when you arrange the numbers to yeild the highest amount possible.
___ ___ ___
l___l l___l l___l
___ ___ ___
l___l l___l l___l
___ ___ ___
l___l l___l l___l

Thanks in advance!


Answers: (Professor Layton for the DS Lite)
Nine squares are carved into a piece of wood.
Arrange nine unique numbers between i and 51 so that any three numbers have the same sum when added vertically, horizontally, or diagonally.
While several combinations are possible, your task is to find the number that occupies the middle square when you arrange the numbers to yeild the highest amount possible.
___ ___ ___
l___l l___l l___l
___ ___ ___
l___l l___l l___l
___ ___ ___
l___l l___l l___l

Thanks in advance!

50 49 48
46 51 47
45 44 43

Thats the answer so put the numbers in the square in that way:D

i dont get it.

26 is the only number that can go in the middle

x-x-malt came close, but not all of the rows and columns add up to the same amount.

Try this one:

50 43 48

45 47 49

46 51 44

Each row, column and diagonal adds up to 141.

I just took a basic 3x3 magic square with the numbers 1 through 9, and increased each number by 42 so they would range from 43 to 51.

Since a "5" has to occupy the center square in a 1 to 9 magic square, I'd guess that 47 (the middle number between 43 and 51) would be the highest possible.



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