Riddles impossible?!
Question: A professor tells her assistant that she dined with three people last night. She also tells him that the sum of the three people's ages is twice the secretary's own age and that the product of the three people's ages is 2,450. Then, she asks him to tell her the ages of the three people. After a while, the assistant tells the professor that he doesn't have enough information to solve the problem. She agrees and adds that she is older than all three people with whom she dined. The assistant, who knows her age, promptly gives the professor the correct ages. The question is: What are the ages of all five people in this story? i'll post the anwser in 4 hours lol don't be rood when answering lol
Answers: A professor tells her assistant that she dined with three people last night. She also tells him that the sum of the three people's ages is twice the secretary's own age and that the product of the three people's ages is 2,450. Then, she asks him to tell her the ages of the three people. After a while, the assistant tells the professor that he doesn't have enough information to solve the problem. She agrees and adds that she is older than all three people with whom she dined. The assistant, who knows her age, promptly gives the professor the correct ages. The question is: What are the ages of all five people in this story? i'll post the anwser in 4 hours lol don't be rood when answering lol
A little suspicious...Aaron copied and pasted that from here:
http://www.calpoly.edu/~mcarlton/solutio...
At least be slick if you're going to cheat dude.
Can I get the points for being such a sly detective, since that dude ruined everyone else's fun?
it's impossible
Consider all factorizations of 2450 into integers a, b, c. (Since
these three variables represent ages, all factors above 98 should
be excluded!) The remaining triples (a,b,c) sum to distinct values
_except_ 50+7+7 = 49+10+5 = 64. Since the assistant did not have
enough information at this point, one of these two triples must be the
correct answer; in particular, the secretary's age is 64/2 = 32.
If the professor is 49 years old or younger, her assertion about
being older than all others at dinner cannot be true; if she is 51
or older, that information would not help the assistant. Hence,
the professor is 50, and her dinner guests had ages 49, 10, 5.
Hey don't cheat i still got the answer.
there's only 2 multiples that divide evenly into 2450...if you go with 5 / 10 (50) you end up with the last being 49. so the ages of the dinner guests were 5 / 10 /49. (the other scenario is 50 x 7 x 7..which disqualifies itself with too much ambiguity)
49 + 5 + 10 = 64
Secretary = 64/2 = 32 years old
Professor = 50