A farmer has a certain number of cows and chickens in his barn. If there are 34 !
Question: Fun question
Answers: Fun question
Not to seem like a prat, but I'll write out my thought process...
34 animals, that I can assume from the problem.
94 legs... 4 legs per cow, 2 per chicken.
I'll let x represent the number of cows, and y represent the number of chickens...
So, x+y=34.
Also, 4x+2y=94.
Multiply the first equation by -2... -2x-2y=-68, and add it to the first equation...
2x=26, so x=13. Since x+y=34, 13+y=34. Therefore, y =21.
13 cows... therefore 21 chickens.
To check it...
4x + 2y = 94
4(13) + 2 (21) = 94
52 + 42 = 94.
Ta da!
13 cows and 21 chickens.
ok
20 chickens
14 cows
there are 34 cows and chickens
12 cows=48 legs
23 chickens= 46 legs
One chicken is missing a head!
OR
13 cows=52 legs
21 chickens=42 legs
First off, we know that there must be 34 animals. We also know that of those animals, they have 94 legs. A simple guess and check process is used. We know that this is not possible because the closest you can come to is 96, and this is with 14 cows and 20 chickens. Unless there are mutations(ie, one of the cows only has 3 legs) then this is not possible.